-15m -30 = -12m +6
3m = 36
m= 36/3 =12
<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation



∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
Answer:
1)0.123( bar on 3)
Let X = 0.123 ( bar on 3)
Then X = 0.1233 --------(1)
Multiply equation (1) by 100 we get,
100X = 12.33 --------(2)
Again multiply equation (2) by 10 we get,
1000X = 123.33 -------(3)
Subtract equation (2) from equation (3) we get,
1000X = 123.33
100X = 12.33
____________
900X = 111
X = 111/900
Hence,
0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.
'of' means mltilply
jane=2/9 of ben
ben=3/4
jane=2/9 of 3/4
jane=2/9 times 3/4=(2*3)/(9*4)=6/36=1/6 miles