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den301095 [7]
3 years ago
6

Un jugador de basquetbol ha realizado los 2/5 del número de puntos conseguidos por su equipo en un partido y otro la tercera par

te del resto. Si los demás jugadores han conseguido 34 puntos, ¿cuántos puntos obtuvo el equipo en el partido?
Mathematics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

85 points

Step-by-step explanation:

Let :

Total points made by team = x

Points made by the player :

2/5 of total = 2x/5

1/3 of the rest :

Points left = x - 2x/5= 3x /5

1/3 of 3x /5

1/3 * 3x / 5

= 3x / 15 = x / 5

Points made by rest of the players = 34 points

Hence, total points scored, x :

x = 34 + 2x /5 + x /5

x = 34 + 3x / 5

x - 3x/5 = 34

2x / 5 = 34

2x = 34 * 5

2x = 170

x = 170 / 2

x = 85

Total points scored by team = 85

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lakkis [162]

From points (2, 0) and (6, 0), you can get base = 6 - 2 = 4.

From point (8, 5), you get a height of length 5.

A = bh/2 = 4 * 5/2 = 10

Area = 10 square units

3 0
3 years ago
Suppose that y varies directly with x
Olin [163]

Answer:

y=6

Step-by-step explanation:

x=20

y=10

x=15 > 20x=15

x=15/20

x=3/5

y=10(3/5)

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8 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
4 years ago
A recipe call for 5 teaspoons of seasoning for every 6 batches of chicken. If you have 12 batches of chicken, how many teaspoons
gayaneshka [121]

You’ll need 10 teaspoons because 6 x 2 is 12, so 5 x 2 is 10

7 0
3 years ago
Read 2 more answers
Please someone answer this
kirill [66]

Answer:

option 2.

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4 0
3 years ago
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