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natita [175]
3 years ago
11

The length of a rectangle is the sum of the width and 1. The area of the rectangle is 20

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
7 0

Answer:

<h2><u>Solution </u><u>:</u><u>-</u></h2>

We know that

Area = Length × Width

Area = w + 1 × w

Area = w² + w

w² + w - 20

w² + (5w - 4w) - 20

(w + 5)(w - 4)

Either

w = -5

or w = 4

Breadth can't be negative

So,

Breadth = 4 units

Vlada [557]3 years ago
5 0

Answer:

4 units

Step-by-step explanation:

Create an equation where w is the width of the rectangle

Use the area formula, A = lw.

Since the length is the sum of the width and 1, it can be represented by w + 1

Plug in this and the area into the formula, and solve for w

A = lw

20 = (w + 1)(w)

20 = w² + w

w² + w - 20

(w + 5)(w - 4)

Solve for w:

w + 5 = 0

w = -5

w - 4 = 0

w = 4

Since the width cannot be negative, the answer must be 4.

So, the width of the rectangle is 4 units.

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Answer:

36 and 72

Step-by-step explanation:

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PLEASE HELP ME OUT <br><br> Convert the following<br><br> 35 mL = _____dL<br><br> 950 g = _____ kg
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Answer:

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Determine the mean and variance of the random variable with the following probability mass function. f(x) = (216/43)(1/6)^x, x =
anzhelika [568]

Answer:

The mean of function provided is 1.186.

The variance of the provided f(x) is 0.198

Step-by-step explanation:

It is provided that the probability mass function is,

f(x)= (214/43)×(1/6)ˣ; x=1,2,3

The mean is calculated as,

E(X)=∑  x × f(x)

        x

=1×(216/43)×(1/6)¹ + 2 × (216/43)×(1/6)² × 3 × (216/43)×(1/6)³

=36/43 + 12/43  +3/43

​  =1.186

​  

The mean of function provided is 1.186

Explanation | Common mistakes | Hint for next step

The expected value of the probability mass function,f(x)= (216/43×(1/6)ˣ

 is 1.1861.186 .

Step 2 of 2

To calculate the variance, first calculate  E(X²)=∑ x² × f(x)

= 1² ×(216/43) × (1/6)¹ + 2² × (216/43) × (1/6)² × 3² × (216/43) ×(1/6)³

=36/43 +24/43 +9/43

=1.605

​  

The variance is calculated as,

V(X) =E(X²) - [E(X)]²

=1.605 -(1.186)²

= 0.198

The variance of the provided f(x) is 0.198

Explanation | Common mistakes

The variance of function f(x)=(216/43) × (1/6)ˣ ; x =1,2,3 is 0.198

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Find two sets of parametric equations for the rectangular equation. y=(x-6)^2-7x.
jekas [21]

The two sets of parametric equations for the rectangular equation are;

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  • If x=7t then y= 49t² - 133t +36.

<h3>What are the parametric equations from the rectangular equation?</h3>

It follows from the task content that the parametric equations can be determined as follows;

By substituting the x= t+6 into the rectangular equation; we have;

y = (t+6-6)²-7(t+6)

y = t²-7t-42.

By substituting the x= 7t into the rectangular equation; we have;

y = (7t-6)² -7(7t)

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y = 49t² - 133t +36.

Read more on parametric equations from rectangular equations;

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