Answer:
c
Step-by-step explanation:
the probability isn't unavailable so it's not A. 0
and it isn't less than 0 because it is still "may occur"
and it is not one because it is still "unlikely"
so its C. close to 0
Given:
To find:
The quadrant in which 
lie.
Solution:
Quadrant concept:
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II, only 
and 
are positive.
In Quadrant III, only 
and 
are positive.
In Quadrant IV, only 
and 
are positive.
We have,
Here, is negative and is also negative. It is possible, if 
lies in the Quadrant IV.
Therefore, the correct option is D.
C) The mean Value is closer to the middle of the range than the Median
Hope this helped!
Answer:
18
Step-by-step explanation:
One way to solve this would be to just solve for random lengths, left to right, until we come to find UC.
We know JK = JH + HM + MK = 82 and JH = 22, so
82 = 22 + HM + MK
subtract 22 from both sides to isolate the unknowns
60 = HM + MK = HK
96 = HK + KU - HU
We know HK = 60
96 = 60 + KU
subtract 60 from both sides to isolate the unknown
We know KU = 36
105 = KN = KU + UC + CN
We know KU = 36 and CN = 51
105 = 36 + 51 + UC
105 = 87 + UC
subtract 87 from both sides to isolate the unknown
18 = UC
UC is what we're looking for, so the problem is solved
