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iVinArrow [24]
4 years ago
14

Math a challenging subject, sigh...

Mathematics
1 answer:
Tom [10]4 years ago
6 0
1340+160=1500
1500-300=1200
100x7=700
1200-700=500
he has $500 left to pay.
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Which criteria for triangle congruence can be used to prove the pair of triangles below are congruent?
Firlakuza [10]

Answer: The correct option is fourth, i.e., SSS.

Explanation:

First write the name of vertices as shown below,

From the figure we can say that in triangle DAB and triangle BCD,

AB=CD

DA=BC

In both triangle the sides BD is common, so,

BD=BD

Since three sides of triangles DAB and triangle BCD are same so by the SSS property of congruent triangle we can conclude that the triangle DAB and triangle BCD are congruent.

Therefore the fourth option is correct.

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3 years ago
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Mary constructed ΔJKL from two angles and their included side. The angles were ∠JKL and ∠KLJ. What was the included side?
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2 years ago
Solve for h<br> A=1/2(a+b)h
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3 0
3 years ago
This is hard pls help
makkiz [27]

The length of the SM parallelogram when the length of the rectangle is 15 cm and width is 8 cm is 8/5 units.

<h3>What is the area of a rectangle?</h3>

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a\times b

Here, (a)is the length of the rectangle and (b) is the width of the rectangle

The length of the rectangle is 15 cm and width is 8 cm. Thus, the area of it is,

A=15\times8\\A=120\rm\; cm^2

All three parts has equal area. Thus, the area of parallelogram NCMA is,

A_p=\dfrac{120}{3}\\A_p=40\rm\; cm^2

MN is the height of the parallelogram. Thus,

A_p=h\times AS\\40=h\times15\\h=\dfrac{40}{15}\\h=\dfrac{8}{5}

Thus, the length of the Sm parallelogram when the length of the rectangle is 15 cm and width is 8 cm is 8/5 units.

Learn more about the area of rectangle here;

brainly.com/question/11202023

#SPJ1

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2 years ago
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