The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
-3 + -3 = 0
-5 + 1 = -4
vector = < 0,-4 >
Every angle of a square equals 90 degrees.
2x - 4 = 90 3y + 6 = 90
2x = 90 + 4 3y = 90 - 6
2x = 94 3y = 84
x = 94/2 y = 84/3
x = 47 y = 28
so x = 47 and y = 28
2.99
2 is a whole number
0.99 = 99/100
your fraction is:
mixed number = 2 99/100
improper fraction = 299/100 (multiply whole number to denominator & then add numerator)
hope this helps
Answer:
Question 7. -2 8. 3/2
Step-by-step explanation:
