Let
d = the total number of dairy cattle
b = the total number of beef cattle
2/3 of the dairy cattle on a farm are in the barn, and we know that 24 dairy cattle are in the barn thus:
(2/3)d = 24
d = 36 dairy cattle
1/4 of the beef cattle are in the barn and there are 16 beef cattle in the barn thus:
(1/4)b = 16
b = 64 beef cattle
64 - 36 = 28
There are 28 more beef cattle on the farm than dairy cattle.
C
The two triangles are similar — that is, the three angles in triangle EDC correspond to those in ABC
The answer is
T2=(P2V2/T1)/P1V1
