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2 years ago

Find mPMA + mCMT. Please help..

Mathematics

1 answer:

juin [17]2 years ago

8 0

PMA = 37

CMT = 101 - 54 =47

Total = 37 + 47 = 84

Answer: A. 84

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What is 3/10 and 1/5 by using common

astra-53 [7]

Answer:

Step-by-step explanation:

5*2=10

10*1=10

so 1/5=2/10

3 0

3 years ago

Check my answer? Please, no joking around guys.

WITCHER [35]

This is a right angle triangle
So we can use the tangent
tan x = 5/20
tan x= 0.25
x=tan^-1 (0.25)
x= 14.04 degrees
So yes you're correct

3 0

3 years ago

Read 2 more answers

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height

Crank

Answer:

a) h = 0.1: $\bar v = -11\,\frac{ft}{s}$ , h = 0.01: $\bar v = -10.1\,\frac{ft}{s}$ , h = 0.001: $\bar v = -10\,\frac{ft}{s}$ , b) The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

Step-by-step explanation:

a) We know that $y = 30\cdot t -10\cdot t^{2}$ describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity ( $\bar v$ ), measured in feet per second, can be done by means of the following definition:

$\bar v = \frac{y(2+h)-y(2)}{h}$

Where:

$y(2)$ - Position of the ball evaluated at $t = 2\,s$ , measured in feet.

$y(2+h)$ - Position of the ball evaluated at $t =(2+h)\,s$ , measured in feet.

$h$ - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

$h = 0.1\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}$

$y(2.1) = 18.9\,ft$

$\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}$

$\bar v = -11\,\frac{ft}{s}$

$h = 0.01\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}$

$y(2.01) = 19.899\,ft$

$\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}$

$\bar v = -10.1\,\frac{ft}{s}$

$h = 0.001\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}$

$y(2.001) = 19.99\,ft$

$\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}$

$\bar v = -10\,\frac{ft}{s}$

b) The instantaneous velocity when $t = 2\,s$ can be obtained by using the following limit:

$v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}$

$v(t) = \lim_{h \to 0} 30-20\cdot t-10\cdot h$

$v(t) = 30\cdot \lim_{h \to 0} 1 - 20\cdot t \cdot \lim_{h \to 0} 1 - 10\cdot \lim_{h \to 0} h$

$v(t) = 30-20\cdot t$

And we finally evaluate the instantaneous velocity at $t = 2\,s$ :

$v(2) = 30-20\cdot (2)$

$v(2) = -10\,\frac{ft}{s}$

The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

8 0

3 years ago

In a particular year, a total of 50,127 students studied in two of the most popular host countries when traveling abroad. If 838

Arlecino [84]

Answer:

In the most popular abroad country: 29,255 students

In the second-most one: 20,872 students

Step-by-step explanation:

Let's write the situation in an equation to help us solve this. X represents the amount of students in the second most popular country. So we know that in total, there's 50,127 students so let's make an equation that equals this. ???????=50,127. As we know, the most popular country has 8383 more students than the second one so we can write it as x+8383 and for the second most popular country, we can write it as x. We know that both of the countries students combined equal 50,127 students so we have our equation. (x)+(x+8383)=50,127 students. After solving the equation, you get x=20, 872. As we know x=the amount of students in the second most popular country which means there's 20,872 students in the second one. Additionally, for the first most popular one, the equation for the amount of students in it is x+8383 so..... 20,872+8383=Total number of students in the most popular one which is 29,255 students.

7 0

2 years ago

If y represents a child's age, which inequality shows that you must be older than 4 to attend an elementary school?

Amiraneli [1.4K]

Step-by-step explanation:

y> 4

y is greater than 4.

hope this helps

8 0

2 years ago