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3 years ago

How do I show my work if these are parallel or not?

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

You can determine if things are parallel if the lines will eventually meet or not. M and N are one line while P and Q are also a line. Therefore, we can say P is one line while M is also one line. The answer would be is that they are parallel, the two lines will not crash with one another. To show your work as if they are parallel, you can continue the lines down and write a note saying they won't collide or you just say they won't collide and are parallel lines.

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jake finishes piano practice at 2:45 p.m. after practicing for 37 minutes. What time does Natalie’s practice start? Natalie’s pr

shutvik [7]

Answer:

3:22

Step-by-step explanation:

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2 years ago

8x - 2 = -9 + 7x this is for solving equations

dimulka [17.4K]

Answer:

x = -7

Step-by-step explanation:

8x - 2(+2)= -9(+2)+ 7x

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3 years ago

Read 2 more answers

The equation of horizontal line passing through (3,-4) is

Greeley [361]

Answer:

y = - 4

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c

where c is the value of the y- coordinates the line passes through

The line passes through (3, - 4 ) with y- coordinate - 4 , then

y = - 4 ← equation of line

8 0

3 years ago

For what values of x is the graph of y equals negative 3 divided by the quantity 4 plus x concave downward?

Elena-2011 [213]

We are given our function as

$y=\frac{-3}{x+4}$

For finding concavity , firstly we will find second derivative

$y'=\frac{d}{dx}\left(\frac{-3}{x+4}\right)$

$=-3\frac{d}{dx}\left(\frac{1}{x+4}\right)$

$=-3\left(-\frac{1}{\left(x+4\right)^2}\right)\cdot \:1$

$y'=\frac{3}{\left(x+4\right)^2}$

now, we can find derivative again

$y''=\frac{d}{dx}\left(\frac{3}{\left(x+4\right)^2}\right)$

$=3\frac{d}{dx}\left(\left(x+4\right)^{-2}\right)$

$y''=3\left(-\frac{2}{\left(x+4\right)^3}\right)\cdot \:1$

$y''=-\frac{6}{\left(x+4\right)^3}$

now, we can know second derivative is undefined when denominator =0

so, we set denominator =0

and then we can solve for x

$x+4=0$

$x=-4$

now, we can draw a number line and locate x=-4

and then we can find sign of second derivative on each intervals

so,

Concave downward interval:

$(-4,\infty)$

6 0

3 years ago

For binomials of the form (x - y) ^ n explain how to determine the sign of a term without writing out the entire expansion

Mnenie [13.5K]

Answer:

When raising an expression of that format to any power, after grouping like terms, you'll always find that the odd numbered terms are positive, and the even numbered terms are negative.

For example:

(x - y)² = x² − 2xy + y²

(x - y)³ = x³ − 3x²y + 3xy² − y³

(x - y)⁴ =x⁴ − 4x³y + 6x²y² − 4xy³ + y⁴

etc.

3 0

3 years ago