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GuDViN [60]
3 years ago
15

Which type of wave is shown in the image?

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0
The answer will be a semestic wave
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Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under
Radda [10]

Answer:

O Charles's law .

Explanation:

Hello!

In this case, since the use of gas laws leads to a good comprehension of how gases behave towards volume, pressure and temperature, we can review that the Boyle's law explains the pressure-volume variation, the Dalton's law the partial pressure effect, the Gay-Lussac's law that of pressure and temperature and the Charles' that of temperature and volume at constant pressure; thus, the answer for the asked question is:

O Charles's law

Best regards!

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3 years ago
“Copper nitrate is a” <br><br> Symbol <br><br> Name <br><br> Chemical formula
umka21 [38]

Answer:

Name!!!!!

Explanation:

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3 years ago
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A nuclear fission reaction has mass difference between the products and the reactants of 3.86 g. Calculate the amount of energy
iris [78.8K]

<u>Answer:</u> The amount of energy released by the reaction is 3.47\times 10^{14}J

<u>Explanation:</u>

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

where,

\Delta m = difference between the masses of products and reactants = 3.86 g = 0.00386 kg    (Conversion factor: 1 kg = 1000 g)

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=(3.86\times 10^{-3}kg)\times (3\times 10^8m/s)^2

E=3.47\times 10^{14}J

Hence, the amount of energy released by the reaction is 3.47\times 10^{14}J

3 0
3 years ago
How does your body help the musculoskeletal preform it’s function
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Explanation:

The musculoskeletal system provides form, support, stability, and movement to the body. It is made up of the bones of the skeleton, muscles, cartilage, tendons, ligaments, joints, and other connective tissue that supports and binds tissues and organs together. ... To allow motion, different bones are connected by joints.

3 0
3 years ago
Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f
N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

<u>Answer:</u> The initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+2B\rightleftharpoons C

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

  • Expression for rate law for first trial:

5.4\times 10^{-3}=k(0.30)^a(0.050)^b ....(1)

  • Expression for rate law for second trial:

1.1\times 10^{-2}=k(0.30)^a(0.100)^b ....(2)

  • Expression for rate law for third trial:

2.2\times 10^{-2}=k(0.50)^a(0.050)^b ....(3)

Dividing 2 by 1, we get:

\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1

Dividing 3 by 1, we get:

\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^1       ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}

Calculating the initial rate of formation of C by using equation 4, we get:

k=1.2M^{-2}s^{-1}

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}

Hence, the initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

8 0
3 years ago
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