Answer:
see explanation below
Explanation:
You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.
The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:
PV = nRT (1)
Now, the density (d) is calculated as:
d = m/V (2)
We can rewrite (2) in function of mass of volume so:
m = d*V (3)
Now, the moles (n) of (1) can be calculated like this:
n = m /MM (4)
If we replace it in (1) and then, (3) into this we have the following:
PV = mRT/MM ----> replacing (3):
PV = dVRT/MM ----> V cancels out so finallly:
P = dRT/MM
d = P * MM / RT (5)
The molar mass of N2O is 44 g/mol So, replacing all the data we have:
d = 1 * 44 / 0.082 * 303
d = 1.77 g/L
Floats or sinks Because of its mass
Answer:
I think w but I don't know
An oxidation-reduction (redox<span>) </span>reaction<span> is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. An oxidation-reduction </span>reaction<span> is any chemical </span>reaction<span> in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</span>
