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AnnyKZ [126]
1 year ago
8

Maalox is the trade name for an antacid and antigas medication used for relief of heartburn, bloating, and acid indigestion. Eac

h 4−mL portion of Maalox contains 320 mg of aluminum hydroxide, 320 mg of magnesium hydroxide, and 32 mg of simethicone. If the recommended dose is two teaspoons four times a day, how many grams of each substance would an individual take in a 12−hour period. (1 teaspoon = 5 mL.)
Chemistry
1 answer:
Sholpan [36]1 year ago
8 0

Maalox is the trade name for an antacid and antigas medication used for relief of heartburn, bloating, and acid indigestion in which

4 ml contains

= 320mg of aluminum hydroxide

= 320mg of magnesium hydroxide

= 32mg of simethicone

recommended doses = 4 times * 2 tea spoon = 8 tea spoon/ day

given = 1 tea spoon = 5 ml

8 tea spoon = 40 ml

hence,

amount of aluminum hydroxide = 320/4 * 40 = 3200mg = 3.2 g

amount of magnesium hydroxide = 320/4 * 40 = 3.2 g

amount of  simethicone = 32/4 * 40 = 320 mg = 0.32g

To know more about antacid visit :

brainly.com/question/1328376

#SPJ9

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liubo4ka [24]

4.79 x 10⁻⁷moldm⁻³

Explanation:

Given parameters:

    pOH of RbOH = 6.32

Unknown:

Molarity of the base = ?

Solution:        

    The pH or pOH scale is used for expressing the level of acidity alkalinity of aqueous solutions.

                      pOH = -log[OH⁻]

  we know the pOH to be 6.32

               6.32 = -log[OH⁻]

               [OH⁻]  = inverse log₁₀(6.32)

                [OH⁻] =  4.79 x 10⁻⁷moldm⁻³

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6 0
3 years ago
Phosphorus crystallizes in several different forms, one of which is a simple cube with an edge length of 238 pm. What is the den
algol13

<u>Answer:</u> The density of phosphorus is 3.81g/cm^3

<u>Explanation:</u>

To calculate the density of phosphorus, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell = 1  (CCP)

M = atomic mass of phosphorus = 31 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = 238pm=238\times 10^{-10}cm    (Conversion factor:  1cm=10^{10}pm  )

Putting values in above equation, we get:

\rho=\frac{1\times 31}{6.022\times 10^{23}\times (238\times 10^{-10})^3}\\\\\rho=3.81g/cm^3

Hence, the density of phosphorus is 3.81g/cm^3

6 0
3 years ago
Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K
Elenna [48]

Answer:

The pressure of CO2 = 0.48 atm

Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)

Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

5 0
3 years ago
What is the Celsius equivalent of 212°f
larisa86 [58]
212 degrees Fahrenheit is equivalent to 100 degrees Celsius.

4 0
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start out as one kind of rock, but large amounts of pressure and heat change them into a different kind.
Eddi Din [679]

Answer:

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