The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
Answer: -6p - 78
Step-by-step explanation:
-5 (3p + 3) + 9(-7 + p)
-15p -15 - 63 + 9p
-6p-78
G(-4)
=1/2((-4)-1)
=1/2(-5)
=-2.5
------------------------------
f(g(-4))
=f(-2.5)
=2(-2.5)+1
=-5+1
=-4
The measures of all of the interior angles of the triangle are 70 degrees, 70 degrees and 40 degrees
<em><u>Solution:</u></em>
Given that exterior angle of triangle is 140 degrees
The exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles
Given that adjacent angles are congruent
Let one of the non adjacent interior angles be "x"
x + x = 140
2x = 140
x = 70
So the two interior angles are 70 degrees and 70 degrees
Let us find the third interior angle
The angle sum property of a triangle states that the interior angles of a triangle always add up to 180 degrees
70 + 70 + third angle = 180
third angle = 180 - 70 - 70
third angle = 180 - 140
third angle = 40 degrees
Thus the measures of all of the interior angles of the triangle are 70 degrees, 70 degrees and 40 degrees
No 6.52 is equal to 6.520.
The reason for this is because even if you add more ceros to the othe side of 6.52 it would not matter unless there is another number other than 0, Like 6.52000000000000001 is bigger than 6.52 ans smaller tahn 6.5200000000000000000000
