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likoan [24]
3 years ago
14

PLEASEE HELP, I’M CONFUSED!

Mathematics
2 answers:
hichkok12 [17]3 years ago
7 0

Answer:

200

Step-by-step explanation:

if x is the original number:

0.7x = 140\\7x = 1400\\x = 200

quester [9]3 years ago
3 0

Answer:

182

Step-by-step explanation:

You might be interested in
Find the quotient if the dividend is 2.26 · 108 and the divisor is 0.013.
Sliva [168]

Answer:

17.38*10^8

Step-by-step explanation:

Step one:

given data

The  dividend is 2.26*10^8 (i rewrote the given data, i hope it was mearnt to be so)

divisor is 0.013.

Step two:

Hence the quotient is the whole number gotten when the dividend is divided by the divisor

quotient= 2.26*10^8/0.013.

quotient= 17.38*10^8

5 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Diego‘s mother is twice as old as he is. She is also as old as the sum of the ages of Diego and both of his younger twin brother
Pavel [41]
Diego's age is 22
And his mother's age is 42
5 0
3 years ago
U0ukj787y8fr7hjhy7 which one
Sedbober [7]

If ABC and DEF are complementary, then the value of x will be,

90 - ABC = x

90 - 53 = x

x = 37°

5 0
2 years ago
Read 2 more answers
Tom's statement shows a previous balance of $2452.64 a payment of $160 a new transactions totaling $138 what is his new balance
Gemiola [76]

His new balance will be $805.8915

<span>4332.75 * 18.6%</span>

4 0
3 years ago
Read 2 more answers
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