The ship is 88.8 miles far from the port at 4 pm.
Given,
The displacement from 1 to 3 in the afternoon.
D1 = 30 miles/hr × 2 hr
= 60 miles to the north
The displacement from 3 till 4 in the afternoon.The ship changes its course 20 degrees eastward at 3 o'clock.
Therefore, D2 = 30 miles/hr × 1 hr
= 30 miles to the 20° north eastward
By combining two vectors, the resulting displacement:
D = √((D1 ₊ D2 × cos(20°))² ₊ (D2 × sin(20°))²
D = √((60 ₊ 30 × cos (20°))² ₊ (30 × sin(20°))²
D = 88.8 miles
Hence the ship is 88.8 miles far away from the port at 4 pm.
Learn more about "Law of sines and cosines" here-
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Answer:
The answer is B. Acute isosceles
Complete Question
Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at 
is?
Answer:
There is no sufficient evidence to support the professor believe
Step-by-step explanation:
From the question we are told that
The population mean is 
The sample size is 
The sample mean is 
The standard deviation is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis is 
The critical value of the level of significance from the normal distribution table is
The test hypothesis is mathematically represented as
substituting values
Looking at the value of t and 
we can see that 
so we fail to reject the null hypothesis.
This mean that there is no sufficient evidence to support the professor believe
Answer:
1. Associative Property of Multiplication
2. Multiplicative Identity Property
3. Multiplicative Inverse Property
4.Additive Identity Property
5. Associative Property of Addition
6. Additive Inverse Property
