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Feliz [49]
3 years ago
12

How much is 2/3 cups plus 1 1/4 cups

Mathematics
1 answer:
Schach [20]3 years ago
5 0
  • Answer:

1\frac{11}{12}

  • Step-by-step explanation:

\frac{2}{3}+1\frac{1}{4}=\frac{2}{3}+\frac{5}{4}=\frac{8}{12}+\frac{15}{12}=\\    \\=\frac{8+15}{12}=\frac{23}{12}=1\frac{11}{12}

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Jillian was asked to translate the expression 9 n into words. She wrote "a number increased by nine. " Which best describes the
statuscvo [17]

A number increased by nine (n + 9) is the same as nine increased by a number (9 + n), the correct option is C.

<h3>What is the pharse in mathematics?</h3>

A mathematical phrase is a set of words or a combination of words and numbers that can be written as a mathematical expression.

Given

Jillian was asked to translate the expression 9 + n into words.

She wrote "a number increased by nine.

The expresion can be written into the two formate which is;

(n+9) and (9+n)

Hence, a number increased by nine (n + 9) is the same as nine increased by a number (9 + n), the correct option is C.

To know more baout pharse click the link given below.

brainly.com/question/22314482

3 0
2 years ago
Based on the line plot, how many batteries lasted more than 5 1/2 hours? *
babunello [35]

Answer:

5 batteries.

Explanation:

"How many batteries lasted more than 5 1/2 hours?" which means it's counting not only 5 1/2, but 5 3/4 and 6 1/4

3 0
3 years ago
Read 2 more answers
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Radical 8 plus radical 18
maxonik [38]

Answer:

5√2

Step-by-step explanation:

√8 + √18

We first have to find what is the largest perfect square that goes into √8:

4 is the largest, so therefore → √8 gives you 2√2:

Work: √4 * √2 → 2 * √2 → 2√2

Now we have to find what is the largest perfect square that goes into √18:

9 is the largest, so therefore → √18 gives you 3√2:

Work: √9 * √2 → 3 * √2 → 3√2

Because 2√2 and 3√2 have the same "base" of √2, they can be added together:

2√2 + 3√2 = 5√2 (The "bases" are to be left alone!)

7 0
3 years ago
you deposit 200 into an account that pays 7% interest compounded quarterly. how much will you have in 5 years
scoray [572]
First, convert R percent to r a decimal
r = R/100
r = 7%/100
r = 0.07 per year,

Then, solve our equation for A
A = P(1 + r/n)nt
A = 200.00(1 + 0.005833333/12)(12)(5)
A = $ 283.53

Summary:
The total amount accrued, principal plus interest,
from compound interest on an original principal of
$ 200.00 at a rate of 7% per year
compounded 12 times per year
over 5 years is $ 283.53.
8 0
3 years ago
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