Zinc and Lead (II) nitrate react to form Zinc Nitrate and Lead.
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Hi there!
We can use the following conversions to solve:
Total mass --> amount of mols --> amount of atoms (Avogadro's number)
Begin by calculating the amount of boron trifluoride in 3.61 grams:
3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃
Use avogadro's number to convert:
0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms
C)4CO2(g) +2H2O(g)
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Answer:
12 valence electrons
Explanation:
Number of valence electrons: 2 carbons (2 x 4 valence electrons= 8e-) and 4 hydrogens (4 x 1 valence electron = 4 e-) added up gives us 12 valence electrons to work with: Counting the bonds we have made shows that we have used up 10 of the 12 valence electrons leaving us with 2 to complete the octets.