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nata0808 [166]
3 years ago
13

If my aunt means degree Celsius or degrees Fahrenheit

Chemistry
1 answer:
JulijaS [17]3 years ago
7 0
If it is 60 Celsius that would conver to fare height by means of this equation; (1.8*60)+32°F
Which would come out to.... 140° Fahrenheit... Hardly seems like chilly conditions.
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Diazomethane, CH2N2, is used in the organic chemistry laboratory despite its danger because it produces very high yields and is
dexar [7]

Answer:

See picture below

Explanation:

You are not providing the starting compound. However, I found a similar question so, I will draw the product of this compound, and then, you follow the same procedure.

As the problem states, the diazomethane is often used in reaction with carboxilic acid. This kind of reaction will do an esterification reaction, and the final product will always result in an esther.

So, with the example I give you here, all you have to do is replace the OH in the carboxilic group of your initial compound, for the OCH₃ group.

See picture below.

Hope this helps

5 0
3 years ago
NEED ASAP!
Harlamova29_29 [7]

Answer:

discoveries that can change little aspects of our daily lives or finding cures for diseases that have hounded humanity, scientists have been hard at work trying to push us toward a brighter future.

Explanation:

thats what i got from my research :D

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3 years ago
What ingredients are needed to make GHB?
Alex Ar [27]
<u>The Ingredients required are...

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5 0
4 years ago
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
Four students wrote down their description of how pollen moves when plants reproduce.
Pachacha [2.7K]

Answer:

Fred

Explanation:

3 0
3 years ago
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