Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Amount of heat required to vaporize 1 mole of lead = 177.7 kJ
Molar mass of lead = 207.2 g
Mass of lead given = 1.31 kg = 1310 g (1kg=1000g)
Heat required to vaporize 207.2 of lead = 177.7 kJ
Thus Heat required to vaporize 1310 g of lead =
Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
C. Weak acids partially ionize
Answer:
E
Explanation:
To know what will happen, we need to know
the total number of electrons the element have.
This can be calculated by adding all the electrons together
That would be 2 + 2 + 6 + 2 + 4 = 16
This shows that the element is sulphur.
Now using the KLMN electronic configuration, sulphur has the shells 2,8,6 meaning there are 2 extra electrons needed for octet configuration to be achieved.
This makes option E the correct answer to the question
The IR spectrum of aldehyde compound will not show evidence of hydrogen bonding. The Infrared (IR) spectrum involves the interaction of infrared radiation with matter. It is used to study and identify chemicals and their properties. Evidence of hydrogen bonding is not shown due to lack of molecular contact.
