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egoroff_w [7]
3 years ago
8

For the following reaction, the equilibrium constant Kc is 2.0 at a certain temperature. The reaction is endothermic. What do yo

u expect to happen to the concentration of NO if the temperature is doubled? 2NOBr( g) ⇌ 2NO( g) + Br 2( g) The change in concentration of [NO] will depend on the size of the vessel. The concentration of NO will increase. The concentration of NO will decrease. A catalyst will be needed to make a change in concentration. There will be no change in [NO].
Chemistry
1 answer:
jeyben [28]3 years ago
7 0

Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

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The total number of protons in this atom is 79 because an atomic number of an element is equal to the number of protons. Here, the atomic number is 79 after adding the given electronic configuration.

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Every atom has a proton, a subatomic particle, in its nucleus. The particle possesses an electrical charge that is positive and opposite to the electrons.

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