Half of all the integers are ... all of the positive "counting numbers".
The total number is infinite, so I can't list them here. But if you start at '1 '
and count, you can never name <em>ALL</em> of them, but you can name <em>as many</em>
of them as you want to.
Answer:
Step-by-step explanation:
Answer:
x < ( 8 - 2b ) / -a
Step-by-step explanation:
For this problem, we simply will solve the inequality for x.
-ax + 2b > 8
-ax > 8 - 2b
x < ( 8 - 2b ) / -a
Note, the comparison is flipped since a negative multiplicand was used to isolate x.
Cheers.
Answers:
Step-by-step explanations:
