Let's start with the given arc and its angle.
The angle YWX is going to be half the arc length.
YWX = 1/2 (226) = 113
Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.
(15x - 8) + 113 = 180
15x + 105 = 180
15x = 75
x = 5
Hope this helps!
Answer:
The width must be greater than 3 meters.
Step-by-step explanation:
Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...
P = 2w + 2(5w) = 12w
We want this to be greater than 36 m, so ...
P > 36 m
12w > 36 m . . . . . . . substitute our expression for P
w > 3 m . . . . . . . . . . divide by 12
The possible values for width are those values that are more than 3 meters.
The answer is 6. The first two absolute values cancel each other and subtracting a negative is adding.
9514 1404 393
Answer:
y = (5/27)(x -7)^2 -5/3
Step-by-step explanation:
Use the given points to find the unknowns in the equation.
If the axis of symmetry is x=7, then the equation can be written in the form ...
y = a(x -7)^2 +b
Filling in the two point values, we have two equations:
0 = a(4 -7)^2 +b ⇒ 9a +b = 0
5 = a(1 -7)^2 +b ⇒ 36a +b = 5
__
Subtracting the first equation from the second, we have ...
(36a +b) -(9a +b) = (5) -(0)
27a = 5
a = 5/27
Substituting that value into the first equation gives ...
9(5/27) +b = 0
5/3 +b = 0
b = -5/3
So, the quadratic can be written in vertex form as ...
y = (5/27)(x -7)^2 -5/3
