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anyanavicka [17]
2 years ago
8

Don't squeeze. Fiver shoppers buy Charmain toilet paper. One charmin out of 10 in this batch is defective-its unsqueezable. You

want to save every one from this catastrophe, so you stop them at the door and ask to squeeze their charmin. After squeezing 5 rolls, what is the possibility that you have located 1 or more defective charmins? Hint start off with the chance that you squeezed no defective rolls.
Mathematics
1 answer:
nikklg [1K]2 years ago
7 0

Answer:

The probability of finding aleast one or more defective charmins = 0.40951

Step-by-step explanation:

The probability of not finding a defective charmin = 1

probability of finding defective charmain = 1-0.1 =0.9

The probability of not finding all five defective item =

Then,

probability of not finding all five defective item=0.59049

Thus,

The probability of finding atleast one or more defective chairmins = 1-0.59049

Therefore,

The probability of finding atleast one or more defective chairmins =0.40951

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An office supply company sells two types of fax
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To solve this problem, we would write a system of linear equations.

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We can proceed to write our equations now.

x + y = 22...equation(i)\\150x + 225y = 3900...equation(ii)

From equation 1

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<h3>The Value of Y</h3>

put equation (iii) into (ii)

150x + 225y =3900\\x = 22-y\\150(22-y)+225y=3900\\3300-150y+225y=3900\\3300+75y=3900\\75y=3900-3300\\75y=600\\75y/75=600/75\\y=8

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From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.

Learn more about system of equations here;

brainly.com/question/13729904

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