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3 years ago

5

Find sin A A. Sin A=4/5

1 answer:

Artemon [7]3 years ago

3 0

If you are required to find A, then A=sin inverse(4/5)

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When using rational expectations, forecast errors will, on average, be ________ and ________ be predicted ahead of time. A) zero

mafiozo [28]

Answer:

A) zero; cannot

Step-by-step explanation:

In line with the principle of rational expectations, expectation errors are unpredictable. The expectations of all available information will not differ from the optimal projections.The word optimal projection is inexorably intertwined with the best guess in rational expectations theory.

4 0

4 years ago

Verdadero o Falso:

crimeas [40]

B is the correct answer

8 0

3 years ago

What is the simplified form of

umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

Step-by-step explanation:

Given the expression

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)$

solving the expression

$=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)$

apply the rule: $a^0=1,\:a\ne \:0$

$=-7+5x^2-x+6-\left(-8x^2+x+3\right)$

$=-7+5x^2-x+6+8x^2-x-3$

simplify

$=13x^2-2x-4$

Therefore, the simplified form is:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0

3 years ago

How to find the perimeter of a right triangle using Pythagorean

dsp73

Answer:

12

Step-by-step explanation:

7 0

3 years ago

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

3 years ago