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3 years ago

Solve the following word problems:

Mathematics

2 answers:

Allushta [10]3 years ago

6 0

Answer:

Step-by-step explanation:

CP = ₹1800

Loss = 5%

$SP =\frac{100-Loss}{100}*CP\\\\= \frac{100-5}{100}*1800\\\\=\frac{95}{100}*1800\\\\$

= ₹ 1710

Loss = CP - SP

= 1800 - 1710

= ₹ 90

irinina [24]3 years ago

4 0

Answer:

His loss is 90

He sold it 1710

Step-by-step explanation:

1) 1800x5/100= 90

2) 1800-90=1710

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Read 2 more answers

6. (09.04 LC)

anzhelika [568]

Given:

The quadratic equation is

$y=6x^2-9x+22$

To find:

The correct application of the quadratic formula.

Solution:

If a quadratic equation is $ax^2+bx+c=0$ , then the quadratic formula is

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$y=6x^2-9x+22$

Putting $y=0$ , we get

$6x^2-9x+22=0$

Here, $a=6,b=-9,c=22$ . Using the quadratic formula, we get

$x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}$

The correct application of the quadratic formula is $x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}$ .

Note: The options are not in proper format.

8 0

3 years ago

Solve the following word problems:​

Solve the following word problems: