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lapo4ka [179]
3 years ago
12

SOMEONE PLEASE HELP ME I’m really confused

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

Were you given a graph or do you have one you can use?

- If you do, all the need to do is plot the points that are shown in the question. -Secondly, You need to join the lines together.

-After that, you need to find the 'middle point' of each line. Eg. If I had a line with 4 spaces in-between it, I would put a point or cross after the 2nd space.

Hope that helped? Sorry if it's too confusing and was useless.

<u><em>In the image the blue shape is the rectangle and the red shape is the rhombus/tilted square.</em></u> (MY DRAWING IS BAD I KNOW DON'T SAY ANYTHING ABOUT IT) Anyways. I still feel like you need to do it yourself as this was assigned to you so get some paper and draw this graph out. Let me know if you need more help!

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Find the product. (-5a2)3 · a5
lesya692 [45]

Answer:

-125a^{11}

Step-by-step explanation:

The expression that we have in this problem is

(-5a^2)^3\cdot a^5

First of all, we proceed by evaluating the power of the term in the brackets. We apply the rule:

(a^m)^n=a^{m\cdot n}

So

(a^2)^3=a^6

Moreover, we have

(-5)^3=-125

Therefore,

(-5a^2)^3=-125 a^6

So now the expression is

-125a^6 \cdot a^5

Now we apply the following rule:

a^m \cdot a^n = a^{m+n}

So we have

a^6\cdot a^5 = a^{6+5}=a^{11}

Therefore, our expression becomes:

-125a^6\cdot a^5=-125a^{11}

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4 years ago
I need help on number 1​
lesya [120]

Answer:

y = -9

Step-by-step explanation:

8 0
3 years ago
The area of a circle is 616 cm². Find its circumference. Use π = 22/7
Inessa [10]

Answer:

A

Step-by-step explanation:

pi*r²=616

22×r²=616×7

r²=4312/22

r=14

now

2piR=2×22/7×14

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2 years ago
Which algebraic expression is equivalent to the expression below?<br> 6(3x-2)
SCORPION-xisa [38]

Answer:

18x - 12

Step-by-step explanation:

multiply each term in the parenthesis by the 6 outside ( distributive law)

6(3x - 2)

= (6 × 3x ) + (6 × - 2) = 18x +(- 12) = 18x - 12


8 0
4 years ago
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