Answer:
B.
Step-by-step explanation:
You can't have the same X values for two different Y values
in this case 19 goes with 11 and 10 in the pairs (19,11) and (19,10)
948/10 = 94.8^3 = 851,971.392
Answer: True
One angle of a right triangle = 90°
Let x = the acute angle of one angle.
Let y = the angle of the other angle.
Because the sum of angles in a triangle is 180°,
x + y + 90 = 180
x + y = 90
y = 90 - x
Therefore the angles for each of the two triangles are
x, 90° - x, 90°.
The two triangles are therefore similar because of AAA (Angle, Angle, Angle).
PART 1If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.
For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²
I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.
PART 2If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.
For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3
I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.
SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%