It is NOT true because space is almost completely empty. There is nothing to transfer the energy from the sun to the earth.
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Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
Answer:
Her full blood type genotype is Dd.
Explanation:
Rh (Rhesus) factor is a type of protein found on the outside of red blood cells. It is genetically inherited. An individual that has this protein is Rh-positive, and the one that doesn't is Rh-negative. The Rh-positive gene is dominant, while the Rh-negative gene is recessive. This means that a person must inherit at least one dominant (D) allele from their parents in order to be Rh-positive.
If Dr. Mrs. Brown is Rh-positive, and her father is Rh-negative, her mother must be Rh-positive (DD or Dd), as well. Her father has two recessive alleles (dd), which means that Dr. Mrs. Brown must have one recessive allele. Since she is Rh-positive, she must have one dominant allele. This makes her genotype Dd.