There not the same
vectors have magnitude and direction scalars on the other hand only have magnitude
Answer:
<h3> in square feet</h3>
Step-by-step explanation:
Area of anything is<u> allways </u>reported <u>in square units</u>. Usually that is square of given unit because it's the simplest way:
R = 50 ft
A = πR² = π•(50 ft)² = π • 50 ft • 50 ft = 2500π ft² ≈ 7854 ft²
{Of course you can re-calculate the units, ex.:
3 feet = 1 yard so 50 ft = 50/3 yd then
A = πR² = π•(50/3 yd)² = π • 50/3 yd • 50/3 yd = 2500/9 π yd² ≈ 872.7 yd² }
Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.
Step-by-step explanation
I copy and pasted the answer
Answer:
D. Tenths
Step-by-step explanation:
Because when you go behind the decimal, it starts out with tenths, then hundredths, and then thousandths. And 6 in the 1st spot behind the decimal so it's tenths.
hope I helped.
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
