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Rina8888 [55]
3 years ago
6

What is the rate of change of the linear relationship modeled in the table? (4 points) x y −2 5 −1 4 0 3 1 2 a −2 b −1 c negativ

e one over two d 1
Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
Dexd txstzysyydsyyszyszzexuexudxduzedzdyys stey d xrzy
Ostrovityanka [42]3 years ago
4 0

Answer:

rate of change=slope= y2-y1/x2-x1

Step-by-step explanation:

x: -2|-1|0|1

y : 5|4|3|2

so choose 2 ordered pairs. in this case, we will choose (-2,5) and (-1,4)

now we plug them in: \frac{4-5}{-1-(-2)}

4-5=-1

-1-(-2)=1

so -1/1 is equal to -1, meaning it's answer option b.

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A farmers field has the dimensions shown. He needs to find the area of the field so that he knows how much he needs to buy .What
kolbaska11 [484]

Answer:

Area of the rectangular Field = 3 8/9 km²

Step-by-step explanation:

Length of the field = 2 1/3 km

Width of the field = 1 2/3 km

Area of a rectangular Field = length × width

= 2 1/3 × 1 2/3

= 7/3 × 5/3

= (7*5)/(3*3)

= 35/9

Area of the rectangular Field = 3 8/9 km²

Perimeter of the rectangular Field = 2(length + width)

= 2(2 1/3 + 1 2/3)

= 2(7/3 + 5/3)

= 2(7+5/3)

= 2(12/3)

=2(4)

= 8 km

Perimeter of the rectangular Field = 8 km

5 0
3 years ago
Order the integers from least to greatest {-11,8,-13,-2,16}
Dovator [93]
Least to Greatest going ⬇
-13
-11
-2
8
16
3 0
3 years ago
A scale on a drawing is .5mm : 4cm. The height of drawing is 4.4 mm. What is actual height of object
ivanzaharov [21]
It would be 4.4mm/.5 mm x 4 cm = 35.2 cm
6 0
3 years ago
9x^2+6x-8 factor trinomia
Yanka [14]
(3x-2)(3x+4) yayyyyy
4 0
2 years ago
Read 2 more answers
John can jog twice as fast as he can walk. He was able to jog the first mile to his grandmas house but then he got tired and wal
statuscvo [17]

Answer:

  12 mph

Step-by-step explanation:

The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...

  (9 mi)(.75 h) = 12 mi/h . . . average jogging speed

__

<em>Check</em>

1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.

4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.

The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)

_____

<em>Comment on the problem</em>

Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.

7 0
3 years ago
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