The equation is given as: v=by/3 but it is actually <span>v=bh/3
</span><span>
Ans, now, we need to solve this for variable h.

So, </span>v=bh/3
On cross multiplying, we get,
3 × v = bh
On dividing the complete equation by "b" we get,
(3×v) / b = (bh)/b

or (3×v) / b = h

Thus, the value of h is : 3v/b

8 0

3 years ago

For some integer n, the first, the third and the fifth terms of an arithmetic sequence are respectively 3n, 5n – 6, and 11n + 8.

Mazyrski [523]

Answer:

a₄=8n+1= -39.

Step-by-step explanation:

1) if a₁=3n; a₃=5n-6 and a₅=11n+8, then it is possible to calculate the difference according to 0.5(a₅-a₃)=0.5(a₃-a₁). Then

2) 0.5(11n+8-5n+6)=0.5(5n-6-3n); ⇔ 6n+14=2n-6; ⇔ n= -5.

3) if n=-5, then the 4th term is:

$a_4=\frac{a_5+a_3}{2}; \ = > \ a_4=\frac{11n+8+5n-6}{2}=8n+1;$

or a₄=-39.

8 0

1 year ago

I need help with this please ​

I need help with this please