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3 years ago

6

If distance, d, is proportional to time, t, and at time t =2.00 seconds, the distance is 6.20 m, find the distance when t = 3.50

s.

1 answer:

Allushta [10]3 years ago

5 0

At 3.5s the distance would be 10.85

Find 1/4th of 2.00 and add that to 6.2

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Determine the amount of water that must be added to a 2-litre solution of sulphuric acid to dilute it from a pH of 2.7 to a pH o

Ksivusya [100]

Answer:

Volume of water added = 2.0 L

Explanation:

Initial pH of the solution = 2.7

[H^+] concentration in 2 L solution of sulfuric acid,

$pH = -log[H^+]$

$[H^+] = 10^{-pH}\ M$

$[H^+] = 10^{-2.7} = 0.001995\ M = 0.002\ M$

Final pH of the solution = 3

Final [H^+] concentration of sulfuric acid,

$[H^+] = 10^{-pH}\ M$

$[H^+] = 10^{-3} = 0.001\ M$

Now,

$M_1V_1=M_2V_2$

$0.002 \times 2.0 = 0.001 \times V_2$

$V_2 = \frac{0.002 \times 2.0}{0.001} = 4.00\ L$

Volume added = Final volume - Initial volume

= 4.0 - 2.0 = 2.0 L

4 0

4 years ago

A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 degrees celsius,

Airida [17]

Answer:

0.714 liter.

Explanation:

Given:

The balloon initially has a volume of 0.4 liters and a temperature of 20 degrees Celsius.

It is heated to a temperature of 250 degrees Celsius.

Question asked:

What will be the volume of the balloon after he heats it to a temperature of 250 degrees Celsius ?

Solution:

By using:

$PV=nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 0.4 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

0.4 liter = $0.4\times10^{-3}=4\times10^{-4} m^{3}$

And initial temperature of balloon, $T_{1}$ = 20°C = (273 + 20)K

= 293 K

Let the final volume of balloon is $V_{2}$

And a given, final temperature of balloon, $T_{2}$ is 250°C = (273 + 250)K

= 523 K

Now, $V_{1}$ = $KT_{1}$

$4\times10^{-4}=K\times293\ (equation\ 1 )$

$V_{2}$ = $KT_{2}$

$=K\times523\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4\times10^{-4}}{V_{2} } =\frac{K\times293}{K\times523}$

K cancelled by K.

By cross multiplication:

$293V_{2} =4\times10^{-4} \times523\\V_{2} =\frac{ 4\times10^{-4} \times523\\}{293} \\ = \frac{2092\times10^{-4}}{293} \\ =7.14\times10^{-4}m^{3}$

Now convert it into liter with the help of calculation done above.

$7.14\times10^{-4} \times1000\\7.14\times10^{-4} \times10^{3} \\0.714\ liter$

Therefore, the volume of the balloon be after he heats it to a temperature of 250 degrees Celsius is 0.714 liter.

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3 years ago

Carbon dioxide (CO2) is a common compound made of

marishachu [46]

Answer is D 2 elements and a total of 3 atoms

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3 years ago

What element has the same number of valence electrons as sulfur?

FinnZ [79.3K]

Oxygen. Is the correct answer

Oxygen has the same number of valence electrons as sulfur. An ion can be an element that gained or lost an electron.

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3 years ago

Which beakers in the model contain solid insoluble substances?

ladessa [460]

Although the models are not provided, I was able to find them and the beakers with solid present in them are:
1C
2A
2C
3A
3C

This is determined by the fact that the beakers all have a piece of closely packed substance laying at the bottom. This closely packed lattice is characteristic of solid substances, and the fact that they exist in the solution in the solid states indicates that they are insoluble.

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4 years ago