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Bumek [7]
3 years ago
14

A galvanic^cell consists of left ompartmcnt with a tin elcctrode in contact with 0.1 M Sn(NO_3)_2(aq) and a right compartment wi

th a lead electrode in contact with 1 times l0^-3 M Pb(NO_3)_2(aq). The relevant reduction potentials are: When this cell is allowed to discharge spontaneously at 25 degree C, which of the following statements is true?
a) Electrons will flow from left to right through the wire.
b) Pb^2+ ions will be reduccd to Pb metal.
c) The concentration of Sn2+ ions in the left compartment will increase.
d) The tin electrode will be the cathodc.
e) No noticeable change will occur, bccausc the cell is a. eqmhbnum.
Chemistry
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

Electrons will flow from left to right through the wire.

Pb^2+ ions will be reduccd to Pb metal.

The concentration of Sn2+ ions in the left compartment will increase.

Explanation:

Looking at the relative electrode potentials of the two metals

Sn= -0.14

Pb=-0.13

Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.

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Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or io
Dmitrij [34]

Answer :

(a) The net ionic equation will be,

2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)

The spectator ions are, NH_4^{+}\text{ and }SO_4^{2-}

(b) The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

The spectator ions are, K^{+}\text{ and }NO_3^{-}

(c) The net ionic equation will be,

Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)

The spectator ions are, K^{+}\text{ and }NO_3^{-}

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The given balanced ionic equation will be,

Cr_2(SO_4)_3(aq)+3(NH_4)_2CO_3(aq)\rightarrow 3(NH_4)_2SO_4(aq)+Cr_2(CO_3)_3(s)

The ionic equation in separated aqueous solution will be,

2Cr^{2+}(aq)+3SO_4^{2-}(aq)+6NH_4^{+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)+6NH_4^{+}(aq)+3SO_4^{2-}(aq)

In this equation, NH_4^{+}\text{ and }SO_4^{2-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)

(b) The given balanced ionic equation will be,

Ba(NO_3)_2(aq)+K_2SO_4(aq)\rightarrow 2KNO_3(aq)+BaSO_4(s)

The ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)+2K^{+}(aq)+2NO_3^{-}(aq)

In this equation, K^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

(c) The given balanced ionic equation will be,

Fe(NO_3)_2(aq)+2KOH(aq)\rightarrow 2KNO_3(aq)+Fe(OH)_2(s)

The ionic equation in separated aqueous solution will be,

Fe^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)+2K^{+}(aq)+2NO_3^{-}(aq)

In this equation, K^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)

3 0
3 years ago
Did a chemical reaction occur while the candle was burning?
liraira [26]

Answer: yes

Explanation:

3 0
3 years ago
Son el punto 2,3,4 por favor
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8 0
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What is the molar mass of just the O in CO2?
Vlad1618 [11]

Answer:

16 g/mol

Explanation:

In CO2, it means we have 1 mole of carbon and 2 moles of oxygen.

However, we want to find the molar mass of just a single mole of oxygen.

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In essence the molar mass is simply the atomic mass in g/mol

8 0
3 years ago
Determine the type of alcohol corresponding to each given description or name. 1-pentanol 3-ethyl-3-pentanol 2-hexanol An alcoho
pochemuha

Answer:

1). 1-pentanol - <u>Primary</u>

2). 3-ethyl-3-pentanol - <u>Tertiary</u>

3). 2-hexanol - <u>Secondary</u>

4). Alcohol with two other carbons attached to the carbon with the hydroxyl group - <u>Secondary</u>

5). Alcohol with one other carbon attached to the carbon with the hydroxyl group - <u>Primary</u>

6). Alcohol with three other carbons attached to the carbon with the hydroxyl group - <u>Tertiary</u>

Explanation:

The distinct types of alcohol have been matched with the categories above as per their descriptions provided. In chemistry, alcohols have been categorized into three different categories namely primary, secondary, and tertiary.

In the primary type, those alcohols are involved in which there is an association of hydroxyl group to a primary atom of carbon along with a minimum of two atoms of hydrogen. Example; ethanol.

In the secondary type, the alcohols have an association of carbon atoms to hydroxyl with a single atom of hydrogen and has a formula of '-CHROH.' Example: 2 - propanol.

In the tertiary alcohols, here the association is between the hydroxyl group with the carbon atom that is saturated and possessing 3 atoms of carbon associated with it. It has a formula of '-CR2OH.' Example:  3-ethyl-3-pentanol, -tert -butyl alcohol, etc.

7 0
3 years ago
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