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o-na [289]
3 years ago
9

If the reactants of a reaction have one s and four of atoms what will the products have

Chemistry
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

The products will also have one S and four O atoms.

Explanation:

According to Law of Conservation of Matter, " Matter can neither be created nor destroyed, but it can be changed from one form into another".

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Which of the following factors affects the amount of heat absorbed by a substance?
Ilia_Sergeevich [38]

Answer:

\boxed{\text{Specific heat capacity of the substance}}

Explanation:

The formula for the amount of heat absorbed by a substance is

q = mCΔT

Thus, the three factors are the

  • mass
  • specific heat capacity
  • temperature change

The only factor that is on your list is

\boxed{\textbf{Specific heat capacity of the substance}}

The shape of the substance has no effect, nor do its melting and boiling points.

3 0
3 years ago
I need to know what occupied vs full means for chemistry
Anastaziya [24]
You can get the answer on quizlet or google
7 0
3 years ago
The atomic radius of a silver atom is 1.44 x 10-10. Give the
professor190 [17]

Answer:

0.144 nm

Explanation:

Silver's electronic configuration is (Kr)(4d)10(5s)1, and it has an atomic radius of 0.144 nm.

5 0
3 years ago
How can you tell if a chemical is a metallic bond?
coldgirl [10]

Answer: In a metallic bond, each metal atom is surrounded by lots of other metal atoms, and they all share their valence electrons. When two oxygen atoms bond, they become a molecule and don't interact much with other molecules.

Explanation:

4 0
2 years ago
How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH
olganol [36]

Answer: 127.5ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.75\times 85\\\\V_1=127.5mL

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

6 0
3 years ago
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