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tia_tia [17]
3 years ago
7

If the cost of half a ton of cement is $185, what is the cost per pound.​

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

$0.185

Step-by-step explanation:

since there are 2000 pounds in a ton, this isn't really possible. But the number is correct.

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I need help I don’t understand this :)
Neko [114]

Answer:

Answer

Step-by-step explanation:

OK, there are 360 students in the whole school and 15 classes there, too.

Each class has an EVEN amount of students, so simply, all you need to do is divide (360 divided by 15)

8 0
3 years ago
Suppose if, instead of depositing the $600 all at once, you deposit nothing at the beginning and you divide up the $600 into 12
AlekseyPX

The balance after one year if you deposit one $50 envelope each month, all year is  $613.95.

<h3>What is the balance after one year?</h3>

The balance after 1 year can be determined using this formula:

Amount deposited monthly x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = interest rate = 5% /12 = 0.417%
  • n = number of years = 1 x 12 = 12

Annuity factor = 1.004167^12 - 1 / 0.00417 = 12.279082

Balance = 12.279082 x 50 = $613.95

To learn more about annuities, please check: brainly.com/question/24108530

7 0
2 years ago
Congruent Triangles ?
mel-nik [20]

Check the picture below.

well, it's noteworthy to say that when dropping a perpendicular line from a right angle in a right triangleto the hypotenuse, we'd end up with 3 similar triangles, a Large a Medium and a Small one, all three similar.

3a)

is the Small similar to the Large one? well, let's notice, they both have a 90° angle and also they share the purple one, similar triangles by AA.

3b)

are the Medium and the Large one similar?  well, let's notice, just like before, they both have a 90° and they also share the green one, similarity by AA.

3c)

are the Small and Medium similar?

if Large ~ Medium

and

Large ~ Small

then

Medium ~ Small.

4 0
3 years ago
 Evaluate.<br>(5 • 8 – 12)(36 ÷ 9 • 4)  
Olenka [21]
(5 x 8 - 12)(36 : 9 x 4)
= (40 - 12)(4 x 4)
= 28 x 16
= 448
6 0
3 years ago
A company is in the business of finding addresses of long-lost friends. The company claims to have a 70% success rate. Suppose t
Galina-37 [17]

Answer:

a) Figure attached

b) E(X) =\mu= np = 9*0.7=6.3

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

c) For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.7)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we can use the following R code:

> x <- seq(0,9,by = 1)

> y <- dbinom(x,9,0.7)

> plot(x,y,main="Histogram",type = "h")

And we can see on the figure attached the solution.

We see that the higher probabilities are from 4 to 9

Part b

The expected value is given by:

E(X) =\mu= np = 9*0.7=6.3

The variance is given by:

Var (X) =\sigma^2= np(1-p) = 9*0.7*(1-0.7)= 1.89

And the standard deviation is:

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

Part c

First we can find the probability that at least two addresses will be found in the list of 9 that we have like this:

P(X \geq 2)

We can use the complement rule and we have:

P(X \geq 2) = 1-P(X

We find the indicidual probabilities:

P(X=0)=(9C0)(0.7)^0 (1-0.7)^{9-0}=0.00001968

P(X=1)=(9C1)(0.7)^1 (1-0.7)^{9-1}=0.000413

P(X \geq 2) = 1-[0.00001968+0.000413]=0.9996

If we use the case of n=8 and we find P(X\leq 2), we got:

P(X \leq 2) = 0.9987

For the case n= 7

P(X \leq 2) = 0.9962

For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

5 0
3 years ago
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