Answer:
0.3830,0.6170
Step-by-step explanation:
Given that a process for manufacturing an electronic component yields items of which 1% are defective.
n =100 and p = 0.01
Here X no of defectives is binomial since independence and two outcomes.
Approximation to normal would be
X is N(![100(0.01) , \sqrt{100(0.01)(0.99)} )](https://tex.z-dn.net/?f=100%280.01%29%20%2C%20%5Csqrt%7B100%280.01%29%280.99%29%7D%20%29)
X is N(1,0.995)
a) the probability that the process continues given the sampling plan described
= ![P(X=0)](https://tex.z-dn.net/?f=P%28X%3D0%29)
(with continuity correction)
=![P(|x|](https://tex.z-dn.net/?f=P%28%7Cx%7C%3C0.5%29%5C%5C%3DP%28%7CZ%7C%3C0.50%29%5C%5C%3D%202%280.1915%29%5C%5C%3D0.3830)
b) the probability that the process continues even if the process has gone bad (i.e., if the frequency of defective components has shifted to 5.0% defective)
1-0.3830
=0.6170
Answer:
u just expand the brackets out and make a linear equation to solve from there
Step-by-step explanation:
Answer:
50,000 pounds
Step-by-step explanation:
1 ton = 2,000 pounds