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natta225 [31]
3 years ago
12

What is the best reason for carbon dioxide existing as a gas at standard temperature and pressure?

Chemistry
1 answer:
vlada-n [284]3 years ago
4 0
The Answer is most likely “A”
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I need help on either question you can answer. Thank you god bless
Stels [109]
<h3>Further explanation</h3>

1.Atomic Number (Z) = Mass Number (A) - Number of Neutrons

neutrons = mass number-atomic number

Atomic mass Cl-37= 17

Mass number Cl-37=37

Neutrons = 37-17=20

2. Mass atom X = mass isotope 1 . % + mass isotope 2.%...

\tt atomic~mass~X=0.0224\times 88+0.7832\times 90+0.1944\times 91=90.1

3. The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

f = c / λ, so :

\tt E\approx f\approx \dfrac{1}{\lambda}

Energy is directly proportional to frequency and inversely proportional to the wavelength

So, as the frequency of photon increases, the energy of photon increases

4. Based on answer number 3 :

A. The wavelength becomes longer, and the energy decreases

7 0
3 years ago
From which source is pomace derived? (1 point)
GrogVix [38]

Answer: unused waste from food processing

Explanation: have you takin the chemical reaction system unit test yet? It’s alternated

6 0
3 years ago
PLEASE HELP, WILL GIVE BRAINLIEST!
Over [174]
Hi,
The purpose of the burning splint is to provide activation energy.
5 0
3 years ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

V_{S_{1}} = 10 mL,       weight of compound = 1 g

       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
3 years ago
Read 2 more answers
The molecule CH20 contains two single bonds and one double bond.<br> True<br> False
dem82 [27]

Answer:

True

Explanation:

The molecule CH20 contains two single bonds and one double bond.

6 0
3 years ago
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