The package should be dropped <u>678 m</u> short of the target.
A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.
The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.
Use the equation,
Write an expression for t, the time taken for the package to fall through y.
Substitute 100 m for y and 9.81m/s² for g.
In the time t the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.
Therefore, the horizontal distance traveled by the package is given by,
If the package is released <u>678m</u> before the target, the package would reach the scientists working in Greenland.
The resultant vector is zero.
Explanation:
When you add displacement vectors using the head to tail method, you follow this procedure:
- Draw the first vector
- Draw the second vector, with its tail starting from the head of the first vector
- Draw the third vector, with its tail starting from the head of the second vector
.. and so on.
The resultant of the all vectors will be the vector connecting the tail of the 1st vector to the head of the last vector.
In this problem, the vectors make a closed polygon: this means that the head of the last vector coincides with the tail of the first vector.
Therefore, this means that the length of the resultant vector is zero.
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Answer:
B. energy
Explanation:
A vector has direction.
Energy does not have a direction.
The frequency of the re-emitted light is identical to that of the absorbed light.
To find the answer, we need to know more about the frequency of light.
<h3> Why the re-emitted light has the same frequency?</h3>
- The wavelength of the light that is momentarily absorbed in glass and then re-emitted is the same, which explains why the re-emitted light has the same frequency as the absorbed light and the frequency of the absorbed light is the same.
- An electromagnetic wave's energy is inversely related to its frequency.
- The relationship between the wave's wavelength and frequency depends on the speed of light:
, c is the speed of light.
- Despite not having mass, light still has energy, and that energy is conserved.
- As a result, in order for there to be energy conservation, the energy of the light that is received and reemitted must be equal.
Thus, we can conclude that, the re-emitted light's frequency matches the absorbed light's frequency.
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