Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
$1.25
+
$1.10
___
$2.35 because the 5 goes to 0 the 2 to 1 and 1 to 1 which makes $2.35
that would be the letter d :)
each value of x has a unique value of y
Answer:
12
Step-by-step explanation:
Because 3 games per month and there are 4 months in a season SO 3*4=12 games
Answer:
I eat 3/10 of the coconut and my friend eats 1/5 which is 2/10.
We both eat 3/10 + 2/10 which is 1/2 of the coconut.