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lys-0071 [83]
3 years ago
14

0° C refers to point of ice

Physics
1 answer:
Rashid [163]3 years ago
5 0

Answer:

The freezing point at which water — a liquid — turns to ice — a solid — is 32°F (0°C). ... It is referred to as the freezing point when temperatures decrease below 32°F (0°C), causing water to change state from a liquid to a solid (ice), as happened with the cup of crushed ice immersed in the very cold salt/ice mixture.

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PLEASE HELP ME!!!!!!!!
Ray Of Light [21]

Answer:

I believe C

Explanation:

i never learned this sorry

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3 years ago
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When you place an egg in water, it sinks. If you add salt to the water, after some time the egg floats. Choose the correct expla
lora16 [44]

Answer:

B

Explanation:

This happens because adding salt to the water decreases Its density. When the density of the water matches that of the egg, the egg becomes neutrally buoyant and floats.

The weight of the egg becomes equal to the upward buoyant force by the water on to the egg and hence, the egg floats.

5 0
4 years ago
A 16.0 kg crate rests on a shelf 1.80 m above the floor in a warehouse. A forklift is used to raise the crate to a shelf 3.30 m
klio [65]

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

<h3>What is potential energy?</h3>

It is the energy due to the position.

A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:

U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J

A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:

U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J

The increase in the potential energy is:

518 J - 283 J = 235 J ≈ 240 J

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

Learn more about potential energy here: brainly.com/question/23979653

#SPJ1

5 0
2 years ago
An isolated charged point particle produces an electric field with magnitude E at a point 2 m away. At a point 1 m from the part
guajiro [1.7K]

Explanation:

The electric field at a distance r from the charged particle is given by :

E=\dfrac{kq}{r^2}

k is electrostatic constant

if r = 2 m, electric field is given by :

E_1=\dfrac{kq}{(2)^2}\\\\=\dfrac{kq}{4}\ .....(1)

If r = 1 m, electric field is given by :

E_2=\dfrac{kq}{r_2^2}\\\\=\dfrac{kq}{1}\ ....(2)

Dividing equation (1) and (2) we get :

\dfrac{E_1}{E_2}=\dfrac{\dfrac{kq}{4}}{kq}\\\\\dfrac{E_1}{E_2}=\dfrac{1}{4}\\\\E_2=4\times E_1

So, at a point 1 m from the particle, the electric field is 4 times of the electric field at a point 2 m.

4 0
3 years ago
Which calculation is an example of velocity
Dmitry_Shevchenko [17]

Answer:

Yes

Explanation:

sun rays towards the earth is an example of velocity

3 0
3 years ago
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