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MatroZZZ [7]
3 years ago
13

When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of

acquiring this charge? Express your answer as a number of electrons.
Physics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

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3 0
3 years ago
30 POINTS!!! CAN U AWNSER IT?? :)
solniwko [45]

Answer:

5235.84 kg

Explanation:

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7 0
2 years ago
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Likurg_2 [28]

Answer: A

Explanation:

7 0
3 years ago
If an atom has an atomic number of 2, it will be stable with 2 electrons in its valence shell. Group of answer choices True Fals
torisob [31]

Answer: True

Explanation:

Atomic number is defined as the number of protons or the number of electrons that are present in an electrically neutral atom.

Atomic number = Number of protons = number of electrons = 2

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The electronic configuration will be 1s^2

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3 0
3 years ago
A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the ro
fgiga [73]

Answer:

The vibrational frequency of the rope is 5 Hz.

Explanation:

Given;

number of complete oscillation of the rope, n = 20

time taken to make the oscillations, t = 4.00 s

The vibrational frequency of the rope is calculated as follows;

Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz

Therefore, the vibrational frequency of the rope is 5 Hz.

8 0
2 years ago
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