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MatroZZZ [7]
3 years ago
13

When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of

acquiring this charge? Express your answer as a number of electrons.
Physics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

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Answer:A generator is the appropriate device to be used.

Explanation:

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2 years ago
A parallel-plate capacitor is formed from two 2.7 cm -diameter electrodes spaced 1.4 mm apart. The electric field strength insid
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Answer:

The potential difference between the plates is 8.4\times10^{3}\ V

Explanation:

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V=8.4\times10^{3}\ V

Hence, The potential difference between the plates is 8.4\times10^{3}\ V

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