Question

James (mass 95.0 kg ) and Ramon (mass 67.0 kg ) are 20.0 m apart on a frozen pond. Midway between them is a mug of their favorite beverage. They pull on the ends of a light rope stretched between them. Ramon pulls on the rope to give himself a speed of 1.10 m/s. What is James's speed?

Answer 1

Answer:

The speed of James is 0.776 m/s

Explanation:

Step 1: Data given

mass of James = 95.0 kg

mass of Ramon = 67.0 kg

We consider James and Ramon and the rope to a single system. This means that the net external forces on the system = 0

.The momentum = 0, so the sum of the momentum of each part must be 0 in total.

Step 2: Calculate the speed of James

m(james) *v(James) = m(Ramon) * v(Ramon)

with m(James) = the mass of James = 95.0 kg

with v(James) = speed of James = TO BE DETERMINED

with m(Ramon) = mass of Ramon = 67.0 kg

with v(Ramon) = speed of Ramon = 1.10 m/s

v(James) =  (m(Ramon) * v(Ramon))/ m(james)

v(James) = (67.0 kg* 1.10 m/s) / 95.0 kg

v(James) = 0.776 m/s

The speed of James is 0.776 m/s