Answer: 115m. Displacement can be taken from the distance between the initial point and the final point. In this case,the displacement is 115m.
Answer:
a

b
Explanation:
From the question we are told that
The velocity of the river due east is 
The velocity of the boat due north is 
The width of the river is 
Generally the velocity of the boat relative to the shore

=> 
=> 
Generally direction of the boat relative to the shore is mathematically represented as

=> ![\theta = tan^{-1}[ \frac{v}{v_1}]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20tan%5E%7B-1%7D%5B%20%5Cfrac%7Bv%7D%7Bv_1%7D%5D)
=> ![\theta = tan^{-1}[ \frac{1.5}{10}]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20tan%5E%7B-1%7D%5B%20%5Cfrac%7B1.5%7D%7B10%7D%5D)
=> 
Generally the distance covered by the boat in the direction of flow of the river before reaching the north shore is mathematically represented as

=> 
=>
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c ) If the speed was doubled: v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
I dont think it can be solved as time is not mentioned
The study of motion is called kinematics.