supplementary angles = 180 degrees
so x = angle 1
y = angle 2
y = 3x-12
x + 3x-12 =180
4x-12 = 180
4x = 192
x = 192/4 = 48
y = 3(48) -12 = 144-12 = 132
132 +48 = 180
the angle is 132
We are given the following variables:
μ = the sample mean = 152 pounds
σ = the standard deviation = 26 pounds
x = the sample value we want to test = 180 pounds
n = the sample size = unknown
MOE = margin of error = 4% = 0.04
Confidence level = 96%
The first thing we can do is to find for the value of z
using the formula:
z = (x – μ) / σ
z = (180 – 152) / 26
z = 1.0769 = 1.08
Since we are looking for the people who weigh more than
180 pounds, therefore this is a right tailed z test. The p value is:
p = 0.1401
Then we can use the formula below to solve for n:
n = z^2 * p * (1 – p) / (MOE)^2
n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2
n = 87.82 = 88
Therefore around 88 people must be surveyed.
Answer:
Step-by-step explanation:
there are 8 numbers
we want one of them (number 4)
which is 1 in 8
that is:
Hello,
First of all the point-slope equation will have this form :
Answer A.
Because :
Answer: The raw score for Daniel's exam grade is 101.69.
Step-by-step explanation:
For x be any random variable.
Formula for z-score :
, where 
= population mean
= population standard deviation.
Let x be the raw score for Daniel's exam grade.
As per given , we have
, 
and z= 1.67 , put these values in the above formula , we get
Hence, the raw score for Daniel's exam grade is 101.69.
