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Grace [21]
3 years ago
14

Describe what a carbon footprint is

Chemistry
1 answer:
monitta3 years ago
4 0

Answer:

the amount of carbon dioxide and other carbon compounds emitted due to the consumption of fossil fuels by a particular person, group, etc.

Explanation:

give me brainliest so i can feed my familia

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I will reward Brainly please help
laila [671]
By crushing a solid into a powder you increase the reaction rate (the chemical reaction rate). By crushing into a powder, you are increasing the surface area, increasing the exposure to the chemical reaction. The smaller the particles, the faster the chemical reaction that will take place. Think about an ice cube put in a pot of boiling water. The whole ice cube will take longer to melt than if you first crushed that ice cube into small pieces. Small pieces of ice put into boiling water would melt very quickly.

Hope this helps!! :)
7 0
3 years ago
Microscopic shells that are buried under the seabed are converted to organic sedimentary rocks. during this process, which prope
RideAnS [48]

the mass of the shells will remain the same because you can not change mass even if you were to leave this planet and go to the moon your weight would change but your mass remains the same

8 0
4 years ago
Why is it good for animals to decompose in the soil of living plants
xeze [42]
Because it helps enriches the soil, just like when you make home made compost you add egg shells and old veggies and stuff all the vitamins enriches the compost.

Hope this helped.
4 0
4 years ago
Calculate the weighted average
padilas [110]
Of what?
Attach a link or pic 
3 0
3 years ago
At a certain temperature, 0.660 mol SO 3 is placed in a 4.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
svet-max [94.6K]

Answer:

Kc=6.875x10^{-3}

Explanation:

Hello,

In this case, for the given chemical reaction at equilibrium:

2 SO_3 ( g ) \rightleftharpoons 2 SO_ 2 ( g ) + O_ 2 ( g )

The initial concentration of sulfur trioxide is:

[SO_3]_0=\frac{0.660mol}{4.00L}=0.165M

Hence, the law of mass action to compute Kc results:

Kc=\frac{[SO_2]^2[O_2]}{[SO_3]^2}

In such a way, in terms of the change x due to the reaction extent, by using the ICE method, it is modified as:

Kc=\frac{(2x)^2*x}{(0.165-2x)^2}

In that case, as at equilibrium 0.11 moles of oxygen are present, x equals:

x=[O_2]=\frac{0.110mol}{4.00L}=0.0275M

Therefore, the equilibrium constant finally turns out:

Kc=\frac{(2*0.0275)^2*0.0275}{(0.165-2*0.0275)^2} \\\\Kc=6.875x10^{-3}

Best regards.

6 0
3 years ago
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