<span>The correct answer is (C) 0.2 mole MgCl2.
according to Van't Hoff factor rule which is the ratio between the actual
concentration of the particles produced when the substance dissolved and
the concentration of the substance as measured from its mass, so here 0.2
mole MgCl2 is the higher van't Hoff factor as it has more ions than other
choices and the higher concentration.
and when the boiling point formula is delta Tb = Kb * m * i.
when delta Tb is the change in boiling point.
and Kb is molal boiling point constant
and m is the molality of the solution
and i is Van't Hoff factor.
so we can see the relationship between i and delta Tb, the greater Van't Hoff factor the higher the boiling point. so 0.2 MgCl2 is the higher boiling point as it is the greater van't Hoff factor.</span>
Answer:
18.01528 g/mol
Explanation:
Using the equation to figure this out
Answer:
bent
Explanation:
The chlorite ion has been pictured in the image attached with its two main resonance contributors.
The ion has four regions of electron density as shown. On the basis of the VSEPR theory, we expect a tetrahedral geometry.
However, the ion is bent due to the effect of the lone pairs on chlorine which is the central atom in the ion. This distorts the bond angle of the ion hence the ion has a bent molecular geometry.
