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nata0808 [166]
3 years ago
13

I Type the expression that results from the following series of

Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

4t - 9

Step-By-Step Explanation:

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What is 2 2/3 x 1 1/6
vovangra [49]

Answer:

2 1/10

Step-by-step explanation:

The decimal form is 2.111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

5 0
3 years ago
Read 2 more answers
what is consecutive whole numbers? I have to write an algebraic expression for the sum of three consecutive whole numbers... :(
Agata [3.3K]

Answer:

Consecutive whole numbers (or integers) are numbers that directly follow one another.

Eg: 1, 2, 3, 4, 5 are consecutive whole numbers.

Step-by-step explanation:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108.

or

let the three consecutive whole numbers is x, x+1,and x+2

x + x+1 + x+2 = 4+2(x+1)

3x+3=4+2x+2

3x-2x=6-3

x=3

the other two numbers are 3+1=4,and 3+2=5

so the three numbers are 3,4 and 5

7 0
3 years ago
Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2
kifflom [539]

Answer:

The solution of the differential equation is y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

<u>i) Using characteristic equation:</u>

The characteristic equation method assumes that y(t)=e^{rt}, where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

y'=re^{rt}

y"=r^{2}e^{rt}

r^{2}e^{rt}+e^{rt}=0

(r^{2}+1)e^{rt}=0

As e^{rt} could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}

Using Euler's formula:

y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]

y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)

y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)

The particular solution of the differential equation is given by:

y(t)_{p}=ASin(2t)+BCos(2t)

y'(t)_{p}=2ACos(2t)-2BSin(2t)

y''(t)_{p}=-4ASin(2t)-4BCos(2t)

So we use these derivatives in the differential equation:

-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)

-3ASin(2t)-3BCos(2t)=Sin(2t)

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)

Using the initial conditions we can check that C1=5/3 and C2=2

<u>ii) Using Laplace Transform:</u>

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]  

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]=\frac{2}{(s^{2}+4)}

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) =\frac{2}{(s^{2}+4)}

(s²+1)·Y(s)-2s-1=\frac{2}{(s^{2}+4)}

(s²+1)·Y(s)=\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}

Y(s)=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}

Y(s)=\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}

Using partial franction method:

\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)=\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}

Y(s)=-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[-\frac{1}{3} \frac{2}{s^{2}+4}]-ℒ⁻¹[2\frac{s }{s^{2}+1}]+ℒ⁻¹[\frac{5}{3}\frac{1}{s^{2}+1}]

y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)

3 0
3 years ago
A) Antoine's family is taking a summer vacation through the northern united states on day one of the trips the family will be tr
kirill115 [55]

Answer:

<h2>621.207km</h2>

Step-by-step explanation:

We are expected to convert from miles to kilometer

first day 85 miles =136.794km

Second day 125 mile=201.168km

third day 176 miles =283.245km

Total distance covered is

136.794km+201.168km+283.245km=621.207km

Therefore the total distance in kilometer is 621.207km

8 0
3 years ago
There are two containers of milk. There is twice as much milk in the first container as in the second. After using 2 gal. of mil
lara [203]
Set equations for both containers:
Condition one: $y=2x$
Condition two: $(y-3)=4.5(x-2)$
plug in $y$ from condition one into the second equation:
$2x-3=4.5x-9$
simplify gives: $2.5x=6$
$\boxed{x=2.4}$
$\boxed{y=4.8}$
8 0
3 years ago
Read 2 more answers
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