Answer:
r equals StartFraction C Over 2 pi EndFraction
Step-by-step explanation:
we know that
The circumference of a circle is equal to
where
r is the radius of the circle
Solve for r
That means -----> isolate the variable r
Divide by 2π both sides
Simplify right side
Rewrite
so
r equals StartFraction C Over 2 pi EndFraction
if we divide 20 by 12, we get a quotient of 1, and a remainder of 8.
1,2,4 & 8
12*2<span> = 24</span>
32*2<span> = 64 </span>
44*2<span> = 88 </span>
6*4 = 24
16*4 = 24
<span>etc. </span>
Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb
