Question

Im almost done with it

Answer 1

Answer:

Area of rectangle = $\mathbf{x^2-4x}$

Perimeter of rectangle = $\mathbf{4x-8}$

Step-by-step explanation:

We are given:

Length of rectangle = x

Width of rectangle = x-4

We are not given if we want to find area of rectangle or perimeter of rectangle.

So, I will be finding both

Area of rectangle

The formula used is: $Area\: of\: rectangle=Length \times Width$

Putting values and finding area

$Area\: of\: rectangle=Length \times Width\\Area\: of\: rectangle=x \times (x-4)\\Area\: of\: rectangle=x^2-4x$

So, we get area of rectangle = $\mathbf{x^2-4x}$

Perimeter of rectangle

The formula used is: $Perimeter \: of\: rectangle=2(Length+ Width)$

Putting values and finding perimeter

$Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8$

So, we get perimeter of rectangle = $\mathbf{4x-8}$

I hope, it can help in solving the question.