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Novosadov [1.4K]
3 years ago
11

What is the median of the data set? 32, 41,43,50,70,73,80,88

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
6 0

Answer:

60

Step-by-step explanation:

1) Find the two middle numbers: 50 and 70.

2) Take the average of both #'s to get your answer: 60.

Jobisdone [24]3 years ago
4 0

Answer:

60

hope this helps

have a good day :)

Step-by-step explanation:

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-1.64 as a mixed number
amm1812
<h2>Answer:</h2><h2>- 1\frac{64}{100} simplified it would be - \frac{16}{25}</h2><h2>Hope this helps!!</h2>

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8 0
3 years ago
Which graph shows a function with a zero of –5?
Vedmedyk [2.9K]

Answer:

Look for the y-intercept where the graph crosses the y-axis. Look for the x-intercept where the graph crosses the x-axis. Look for the zeros of the linear function where the y-value is zero.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Lucy went to buy apples, she bought the first two for the full price and the last one for half the price. Is the relationship be
Anit [1.1K]
No it is not proportional. Since she brought the last apple for 1/2 the price, the equation won’t be linear (straight line) anymore so it won’t be proportional. Proportional means the same unit rate.
4 0
3 years ago
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
4 years ago
If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable
kkurt [141]

Answer:

The answer is "\frac{26}{7}"

Step-by-step explanation:

The whole question can be found in the file attached.

\to x + \frac{5}{7} = \frac{31}{7}\\\\

Subtracting the \frac{5}{7} from both sides of the equations:

\to x +\frac{5}{7}  - \frac{5}{7}  = \frac{31}{7}  - \frac{5}{7} \\\\

                    = \frac{31-5}{7} \\\\= \frac{26}{7} \\\\

5 0
3 years ago
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