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finlep [7]
3 years ago
6

Evaluate: f(x)=3x-10 if x=-1

Mathematics
2 answers:
Serga [27]3 years ago
8 0

Answer:

-13

Step-by-step explanation:

f(x)=-3-10

f(x)=-13

VMariaS [17]3 years ago
5 0

Answer:

-13

Step-by-step explanation:

if x=-1 then 3x=-3-10=-13

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Peyton has a number cube and a
Andreyy89

Answer:

Hello Darling! Answer: 14%

Step-by-step explanation:

Now I'm not always accurate, I can re-check myself if you think it isn't right! c;

8 0
3 years ago
What is the probability of getting an odd sum of the scores in a throw of two dice?
gogolik [260]
N(s) = 36
n(F) = 18
P(E) = 18 / 36
        = 1/2.
8 0
3 years ago
What is meant by the term "90% confident" when constructing a confidence interval for a mean? Group of answer choices
Harman [31]

Answer:

The question is not complete, below is the complete question:

What is meant by the term 90% confident? when constructing a confidence interval for a mean?

a. If we took repeated samples, approximately 90% of the samples would produce the same confidence interval.

b. If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the sample mean.

c. If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the true value of the population mean.

d. If we took repeated samples, the sample mean would equal the population mean in approximately 90% of the samples.

Answer:

The correct answer is:

If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the true value of the population mean.  (c)

Step-by-step explanation:

a 90% confidence level means that if repeated samples were taken, 9 out of 10 times, the confidence intervals of the sample chosen will be close to the mean (true value), which is a true representation of the population parameter. when using confidence intervals, there are always margins of allowable accuracy, and this is suggested by using standard diviations snd variances.

I attached a simple document to this answer that will give you more insight into confidence intervals used in statistics.

Download pdf
7 0
3 years ago
What Rato is equivalent to 4 to 10
aksik [14]

Answer:

1 to 2.5

Step-by-step explanation:

4/2=2

10/2=5

2/2=1

5/2=2.5

so 1 is to 2.5

5 0
4 years ago
If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 ov
Nataly_w [17]

Answer:

A + B + E = 32

Step-by-step explanation:

Given

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

Required

Find A +B + E

We have:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

Using integration by parts

\int {u} \, dv = uv - \int vdu

Where

u = x^2 and dv = e^{-4x}dx

Solve for du (differentiate u)

du = 2x\ dx

Solve for v (integrate dv)

v = -\frac{1}{4}e^{-4x}

So, we have:

\int {u} \, dv = uv - \int vdu

\int\limits {x^2\cdot e^{-4x}} \, dx  = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx

-----------------------------------------------------------------------

Solving

\int xe^{-4x} dx

Integration by parts

u = x ---- du = dx

dv = e^{-4x}dx ---------- v = -\frac{1}{4}e^{-4x}

So:

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x}  -\frac{1}{4}e^{-4x}

So, we have:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x}  -\frac{1}{4}e^{-4x}]

Open bracket

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x}  -\frac{1}{8}e^{-4x}

Factor out e^{-4x}

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}

Rewrite as:

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}

Recall that:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}

By comparison:

-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2

-\frac{1}{8}x = -\frac{1}{64}Bx

-\frac{1}{8} = -\frac{1}{64}E

Solve A, B and C

-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2

Divide by -x^2

\frac{1}{4} = \frac{1}{64}A

Multiply by 64

64 * \frac{1}{4} = A

A =16

-\frac{1}{8}x = -\frac{1}{64}Bx

Divide by -x

\frac{1}{8} = \frac{1}{64}B

Multiply by 64

64 * \frac{1}{8} = \frac{1}{64}B*64

B = 8

-\frac{1}{8} = -\frac{1}{64}E

Multiply by -64

-64 * -\frac{1}{8} = -\frac{1}{64}E * -64

E = 8

So:

A + B + E = 16 +8+8

A + B + E = 32

4 0
3 years ago
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