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liubo4ka [24]
3 years ago
9

In the accompanying parallelogram ABCD, find the measure of angle D. A) 70° B) 20° C) 110° D) 290°

Mathematics
1 answer:
Solnce55 [7]3 years ago
8 0
A square (or in this case parallelogram) has a measure of 360 degrees. In parallelograms, the opposite angles are congruent therefore: <A = <C and <B = <D. To solve the problem you would do 360 - (<A + <C) then divide by (1/2) since <B and <D are the same. So, 360 - 140 = 220; 220/2= 110. In conclusion, <D = 110. Answer Choice: C
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Use the diagram to answer the following questions​
n200080 [17]

Answer:

  a. line AR, line AV

  b. plane TSR, plane QTZ, plane RSZ

  c. A, R, V

  d. Q, R, S, T

  e. QR

  f. RQ, RS

Step-by-step explanation:

a. In addition to a name given to a line ("line p"), a line can be named by any two points on that line. Here, possible names are ...

  line AR, line RA, line AV, line VA, line RV, line VR

any two of these names will appropriately answer this part of the question.

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b. In addition to a name given to a plane ("plane W"), a plane can be named by any three points in that plane. Here, there are 5 named points in the plane (3 of which are collinear), so there are 54 possible different names for the plane. Some of them are ...

  plane RST, plane TSR, plane QTZ, plane RSZ

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c. In this diagram, each of the lines shown has three named points on it. Possible answers to this part of the question are ...

  {Q, R, S} or {A, R, V}

__

d. Any four of the 5 named points shown in plane W will serve to answer this question. Possible answers are ...

  {R, S, T, Z} or  {Q, S, T, Z} or  {Q, R, T, Z} or  {Q, R, S, Z} or  {Q, R, S, T}

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e. Any pair of collinear points will name a line segment. Here, there are 12 possible names for line segments, including ...

  QR, RQ, QS, SQ, RS, SR, AR, RA, ...

__

f. Opposite rays can be named by choosing the end point as the middle of three collinear points. Here, the only such middle point is R. We can name pairs of opposite rays on either line. The endpoint of the ray is named first.

  {RA, RV}  or  {RQ, RS}

7 0
4 years ago
Solve the following: 2(5x-3)
Otrada [13]

Answer:

The vale of x is 3/5.

Step-by-step explanation:

First you have to expand out :

2(5x - 3)

= 2(5x) - 2(3)

= 10x - 6

Next you have to solve it by adding 6 to both sides :

Let expression = 0,

10x - 6 = 0

10x - 6 + 6 = 0 + 6

10x = 6

x =  \frac{6}{10}

x =  \frac{3}{5}

6 0
3 years ago
Read 2 more answers
How to write 710,200 in word form
Vilka [71]
Word Form: Seven hundred ten thousand two hundred.
8 0
3 years ago
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Which hyperbola’s asymptote rectangle has the greatest perimeter?
Vitek1552 [10]

Answer:

The greatest perimeter is in (D) ⇒ the perimeter = 60 units

Step-by-step explanation:

* In the hyperbola

- The standard form of the equation of a hyperbola with

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

∵ the length of the transverse axis is  2a

∵ the length of the conjugate axis is  2b

∴ The perimeter of asymptote rectangle is 2(2a + 2b)

* Lets check the answers to find the greatest perimeter

A) (x - 4)²/11² - (y + 2)²/3² = 1

* Compare it with the standard form equation

∵ a = 11 ⇒ 2a = 22

∵ b = 3 ⇒ 2b = 6

∴ The perimeter = 2(22 + 6) = 56

B) (x - 2)²/4² - (y + 1)²/10² = 1

* Compare it with the standard form equation

∵ a = 4 ⇒ 2a = 8

∵ b = 10 ⇒ 2b = 20

∴ The perimeter = 2(8 + 20) = 56

C) (x + 5)²/5² - (y - 3)²/9² = 1

* Compare it with the standard form equation

∵ a = 5 ⇒ 2a = 10

∵ b = 9 ⇒ 2b = 18

∴ The perimeter = 2(10 + 18) = 56

D) (x - 7)²/8² - (y - 2)²/7² = 1

* Compare it with the standard form equation

∵ a = 8 ⇒ 2a = 16

∵ b = 7 ⇒ 2b = 14

∴ The perimeter = 2(16 + 14) = 60

* The greatest perimeter is in (D)

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