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lions [1.4K]
3 years ago
15

1. How much power does a light bulb contain if it does 600J of work in 5 seconds?

Physics
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

120 watts

Explanation:

#1: 120 watts

#2: 667 watts

#3: 3 watts

#4: i forgot how to do this one

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EXTREME HELP!!!!
mrs_skeptik [129]

the anwser is c is always the best anwser


8 0
3 years ago
How and why does air pressure change with altitude in the atmosphere?
wlad13 [49]
Pressure with Height: pressure decreases with incrementing altitude. The pressure at any caliber in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a homogeneous surface at lower calibers.
5 0
3 years ago
a 70 kg skydiver opens her parachute. The force due to air resistance is now 1200 N. what is the acceleration of the skydiver
Natasha_Volkova [10]
Around 50 I think so
7 0
3 years ago
An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu
Maru [420]

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

Learn more about work done on a charge here:

<u>brainly.com/question/13946889</u>

#SPJ4

4 0
2 years ago
A 10.0-kg box starts at rest on a level floor. An external, horizontal force of 2.00 × 102 N is applied to the box for a distanc
Harman [31]

Answer:

vf = 11.2 m/s

Explanation:

m = 10 Kg

F = 2*10² N

x = 4.00 m

μ = 0.44

vi = 0 m/s

vf = ?

We can apply Newton's 2nd Law

∑ Fx = m*a   (→)

F - Ffriction = m*a  ⇒  F - (μ*N) = F - (μ*m*g) = m*a   ⇒  a = (F - μ*m*g)/m

⇒    a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²

then , we use the equation

vf² = vi² + 2*a*x    ⇒    vf = √(vi² + 2*a*x)

⇒   vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s

7 0
3 years ago
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