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lions [1.4K]
2 years ago
15

1. How much power does a light bulb contain if it does 600J of work in 5 seconds?

Physics
1 answer:
dimaraw [331]2 years ago
5 0

Answer:

120 watts

Explanation:

#1: 120 watts

#2: 667 watts

#3: 3 watts

#4: i forgot how to do this one

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Describe how we know the plates once formed a supercontinent and how we know this.
Lady_Fox [76]

Answer:

<h3>How did scientists “discover” Pangea and other supercontinents of the past?</h3>

Nowadays, they can study the geologic record and use radioactive dating, seismic surveys, and other technologies to construct maps of how the world looked at various points in Earth's history.

3 0
2 years ago
Plz explain the answers with steps and a little bit of explanation. I really need the answers for my exam tomorrow! Please help
DochEvi [55]
Here's what you need to memorize for your exam tomorrow.

Distance = (speed) x (time) .

That's it. Memorize it.

-- If the question wants you to find speed, use it exactly in that form.

-- If the question wants you to find speed, then divide each side by (time)
and it says

. Time = (distance) / (speed) .

-- If the question wants you to find time, then divide each side by speed,
and it says

. Time = (distance) / (speed) .

So if you memorize that one equation ... Distance = (speed) x (time) ...
you can solve ANY problem to find distance, speed, or time.

On the sheet in the picture . . . . .

#2). The question is "How long ?". That's TIME that you have to find.
Use the equation in the form of

. TIME = (distance) / (speed)

. = (60 km) / (48 km/h)

. = 1.25 hours .

#3). This one wants you to find SPEED. Use the equation in the form of

. SPEED = (distance) / (time)

but be careful. The time has to be in hours. 55 minutes = 55/60 of an hour.

. SPEED = (distance) / (time)

. = (60 km) / (55/60 hour)

. = (60 x 60 km) / (55 hour)

. = 65.45 km/hr .

#4). This one wants you to find TIME. (It says "How long ?".)

It's two trips, so you have to find the time for each trip.

First trip: TIME = (distance)/(speed) = (24 km)/(65 km/hr) = 0.369 hr

Second trip: TIME = (distance)/(speed) = (50 km)/(80 km/hr) = 0.625 hr

Total time for both trips = (0.369 hr) + (0.625 hr) = 0.994 hour
7 0
3 years ago
The graph shows a wave that oscillates with a frequency of 60 Hz. Based on the information given in the diagram, what is the spe
Snezhnost [94]

Answer:

900 cm/s or 9 m/s.

Explanation:

Data obtained from the question include the following:

Length (L) = 30 cm

frequency (f) = 60 Hz

Velocity (v) =.?

Next, we shall determine the wavelength (λ).

This is illustrated below:

Since the wave have 4 node, the wavelength of the wave will be:

λ = 2L/4

Length (L) = 30 cm

wavelength (λ) =.?

λ = 2L/4

λ = 2×30/4

λ = 60/4

λ = 15 cm

Therefore, the wavelength (λ) is 15 cm

Now, we can obtain the speed of the wave as follow:

wavelength (λ) = 15 cm

frequency (f) = 60 Hz

Velocity (v) =.?

v = λf

v = 15 × 60

v = 900 cm/s

Thus, converting 900 cm/s to m/s

We have:

100 cm/s = 1 m/s

900 cm/s = 900/100 = 9 m/s

Therefore, the speed of the wave is 900 cm/s or 9 m/s.

5 0
3 years ago
Trong máy phát điện xoay chiều ba pha khi tổng điện áp tức thời của cuộn 1,2 là e1+e2=120V thì điện áp tức thời của cuộn 3 là
NARA [144]

Answer:

I just noticd i dont speak this launguage

Explanation:

8 0
3 years ago
A uniform electric field is directed parallel to the +y axis. If a positive test charge begins at the origin and moves upward al
lukranit [14]

Answer: option 1 : the electric potential will decrease with an increase in y

Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below

V = kq/y

Where k = 1/4πε0

Where V = electric potential,

k = electric constant = 9×10^9,

y = distance of potential relative to a reference point, ε0 = permittivity of free space

q = magnitude of electronic charge = 1.609×10^-19 c

From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.

We have that

V = k/y

We see the potential(V) is inversely proportional to distance (y).

This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.

This fact makes option 1 the correct answer

3 0
3 years ago
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